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aev [14]
3 years ago
5

Use the method of ELIMINATION to solve the system. You must SHOW ALL WORK. Make sure you have an answer for both x and y.

Mathematics
2 answers:
jekas [21]3 years ago
6 0

Answer:

<h3>Required <u>Answer</u><u>:</u><u>-</u></h3>

\sf 4x+8y=10\dots\dots (1)

\sf -4x+2y=-30\dots\dots (2)

  • by adding eq (1) and eq (2) we get

{:}\longrightarrow\sf 4x+8y=20

{:}\longrightarrow\sf -4x+2y=-30

<h2>__________________________</h2>

{:}\longrightarrow\sf 10y=-10

{:}\longrightarrow\sf y={\dfrac {-10}{10}}

{:}\longrightarrow{\underline{\boxed{\bf y=-1}}}

  • Substitute the value in eq (2)

{:}\longrightarrow\sf -4x+2 (-1)=-30

{:}\longrightarrow\sf -4x-2=-30

{:}\longrightarrow\sf -4x=-30+2

{:}\longrightarrow\sf -4x=-28

{:}\longrightarrow\sf x={\dfrac {-28}{-4}}

{:}\longrightarrow{\underline{\boxed{\bf x=7}}}

\therefore{\underline{\boxed{\bf (x,y)=(7,-1)}}}

Reptile [31]3 years ago
6 0
(7,-1) will be you’re answer
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Select all ratios equivalent to 20:15
Radda [10]

Answer:

b and c

Step-by-step explanation:

6 0
2 years ago
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Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to f
Angelina_Jolie [31]

Answer:

P(z>1.51) =1-P(Z

And i fwe look into the normalstandar dtable we can find the desired probability:

P(z>1.51) =1-P(Z

And then the The area to the right of z = 1.51 is 0.0655

Step-by-step explanation:

For this case we want to find the following probability:

P(z>1.51)

And for this case we can use the normal standard distribution and the complement rule and we have this:

P(z>1.51) =1-P(Z

And i fwe look into the normalstandar dtable we can find the desired probability:

P(z>1.51) =1-P(Z

And then the The area to the right of z = 1.51 is 0.0655

7 0
3 years ago
You wish to purchase a new car and can afford monthly repayments of up to $250 per month. You see a car you like for $12,000 and
White raven [17]

Answer:

Since the finance’s monthly required payment of $304.07 is greater than the $250 monthly that you can afford, this implies that you CANNOT afford to purchase the car on finance.

Step-by-step explanation:

The monthly required payment of the finance can be calculated using the formula for calculating the present value of an ordinary annuity as follows:

PV = M * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)

Where;

PV = Present value or finance amount = $12,000

M = Finance’s monthly required payment = ?

r = Monthly interest rate = Annual interest rate / 12 = 17.9% / 12 = 0.179 / 12 = 0.0149166666666667

n = number of months = Number of years * 12 = 5 * 12 = 60

Substitute the values into equation (1) and solve for M, we have:

$12,000 = M * ((1 - (1 / (1 + 0.0149166666666667))^60) / 0.0149166666666667)

$12,000 = M * 39.464764662266

M = $12,000 / 39.464764662266 = $304.07

Since the finance’s monthly required payment of $304.07 is greater than the $250 monthly that you can afford, this implies that you CANNOT afford to purchase the car on finance.

4 0
3 years ago
How do I do this trying my best but I can’t please help T_T
Sever21 [200]

Use algebra.

Let the number of stickers each had in the beginning = x stickers.

Ray lost 10 we represent this by

x - 10 ( = no. stickers he has now)

Tom bought 200 so the number of stickers he now has

= x + 200

Rays has 1/4 as much as Tom so we can now create the equation

1/4(x + 200) = x - 10

Soling for x:-

1/4 x + 50 = x - 10

60 = 3/4 x

x = 60 * 4/3 = 80

Answer they had 80 stickers at first.

4 0
3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
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