Write x^2 + 6x -7 in the form (x+a)^2 +b where a and b are integers please

Mathematics

1 answer:

ANTONII [103]4 years ago

3 0

Answer:

$(x + 3) {}^{2} - 16$

Step-by-step explanation:

${x}^{2} + 6x - 7 = (x + 3) {}^{2} - (3) {}^{2} - 7 \\ = (x + 3) {}^{2} - 16$

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