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wariber [46]
3 years ago
8

Need help on math again plz

Mathematics
2 answers:
EastWind [94]3 years ago
7 0

Answer:

Socratic app

Step-by-step explanation:

it will help you

aliya0001 [1]3 years ago
7 0

Answer:

I can't see the image

Step-by-step explanation:

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Step-by-step explanation:

18 x 50 = 900

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Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h
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Answer:

\frac{4}{3}

Step-by-step explanation:

The area of a regular octahedron is given by:

area = 2\sqrt{3}\ *edge^2. Let a is the length of the edge (diagonal).

area = 2\sqrt{3}\ *a^2

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a

The area of a tetrahedron is given by:

area = \sqrt{3}\ *edge^2 = \sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3}    *a^2

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = \frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}

7 0
3 years ago
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Step-by-step explanation:

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ANSWER SHOWN IN THE DOCUMENT ATTACHED TO THIS

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