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Anna [14]
2 years ago
11

Suppose you flip 1000 coins. what is the probability of getting exactly 500 heads

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0
<span>Suppose you flip 1000 coins. what is the probability of getting exactly 500 heads so itd be 
</span>1/500
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Thank you guys fir the help
KiRa [710]

9514 1404 393

Answer:

  A

Step-by-step explanation:

The function f(x) is required in the numerator, eliminating choices C and D.

The restriction is that function g cannot be zero, so we cannot have ...

  3x +2 = 0

  3x = -2

  x = -2/3 . . . . . eliminates choice B; confirms choice A

7 0
2 years ago
Equivalent fractions for 15/35
Anit [1.1K]
\frac{15}{35} /5 \\  \frac{15/5}{35/5}  \\  \frac{3}{7}

That's the simplest form of 15/35. You can use 3/7 to get other equivalent fractions by multiplying the numerator and denominator by the same number. Other examples are 9/21, 6/14, and 12/28.
Hope this helps!

5 0
3 years ago
Margaret drank 1/6 of a 36oz. bottle of soda. She gives the
podryga [215]
Sorry man but I have no idea you could try google
4 0
3 years ago
chef johnson used 4 1/2 cups of flour to make 4 fruitcake. how many cups of flour are needed for 1 fruitcake
Katyanochek1 [597]
Yes I’m going back to the sun yet I have a couple things that you
6 0
2 years ago
Read 2 more answers
A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending
Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: \frac{71}{6} = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: \frac{71}{7} = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: \frac{71}{8} = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

6 0
3 years ago
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