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Aleks [24]
3 years ago
6

Calculate the length of AB. *

Mathematics
1 answer:
arsen [322]3 years ago
4 0

Answer:

the answer will be 9.6 cm

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Find the difference write the answer in simplest form 11/18 -1/6
nevsk [136]

Answer:

4/9

or

0.4

Step-by-step explanation:

7 0
2 years ago
A classic counting problem is to determine the number of different ways that the letters of millennium can be arranged. Find tha
Eddi Din [679]

Answer:

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of letters of the word "millennium" = 10

Letters repeated:

m = 2 times

i = 2 times

l = 2 times

n = 2 times

2. The number of different ways that the letters of millennium can be arranged is:

We will use the n! or factorial formula, this way:

10!/2! * 2! * 2! * 2!

(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)

3'628,800/2*2*2*2 = 3'628,800/16 = 226,800

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

7 0
2 years ago
Please answer these questions quick thank you!
BabaBlast [244]

Answer:

3

Step-by-step explanation:

8 0
2 years ago
4y = 5x is this a direct variation?
Alenkasestr [34]

Answer:

5/4

Step-by-step explanation:

4y = 5x Divide by 4

y = (5/4) x

To make y = kx from y = (5/4) x

k must be (5/4)

k = 5/4

3 0
2 years ago
Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n equals
Alekssandra [29.7K]

Answer:

(0.767,0.833)

Step-by-step explanation:

The 95% confidence interval for population proportion p can be computed as

p-z_{\frac{\alpha }{2} } \sqrt{\frac{pq}{n} }

The z-value associated with 95% confidence level is 1.96.

whereas p=x/n

We are given that x=440 and n=550.

p=440/550=0.8

0.8-1.96\sqrt{\frac{0.8(0.2)}{550} }

0.8-1.96\sqrt{\frac{0.16}{550} }

0.8-1.96\sqrt{0.00029 }

0.8-1.96(0.01706)

0.8-0.03343

0.76657

Thus, the required confidence interval is

0.767<P<0.833  (rounded to 3 decimal places)

Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)

3 0
2 years ago
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