Answer:
Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.
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Answer:
x = 17
Step-by-step explanation:
5x + 29 + 2x + 32 = 180 (linear pair means that these angles add up to 180 cos they are in a line)
7x = 119
x = 17
Answer:
23.5 inches^2
Step-by-step explanation:
Area of triangle = 1/2 * base * height
area = 1/2 * (5+2) * (5+4)
area = 31.5 in^2
Area of rectangle = length * breadth
area = 4 * 2
area = 8 in^2
Area of figure = area of triangle - area of rectangle
area = 31.5 - 8
area =23.5 in^2
The number in parenthesis after f is the x coordinate. Basically, it says which y coordinate is tied with an x value. In choice a, it says that when x is 0 y is 3, etc.
So, you can look at the graph to see which answer choice has a point from the graph. Choice a says (0,3), and that does not match. Choice b says (5,-1) and that does match. So the answer is B.
*(x,y)*
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
