Answer:
The linear velocity of the racquet at the point of contact with the ball is 6 m/s.
Explanation:
Given;
angular velocity of the racquet, ω = 12 rad/s
distance of strike, r = 0.5 m
The linear velocity of the racquet at the point of contact is given by;
V = ωr
V = (12)(0.5)
V = 6 m/s
Therefore, linear velocity of the racquet at the point of contact with the ball is 6 m/s.
1. I think it's the trails left by an electron as it moves around the nucleus.
2. The atomic number is the number of protons so it is 8.
3. It's mass is lowered but it is still the same element.
To determine the distance that you would travel by.
Simply convert 15 minutes to seconds which would be 900 seconds.
Then solve for distance, which would be
D = r • t
D = 12 m/s • 900 s
D =10 800 m.
This is the distance that you had ran for.
Answer:
E1_max = 866 V/m...................................... option D
Explanation:
We know that for linearly polarized light, relation between intensity and electric field is given by:
I_avg = (1/2)*c*e0*E_max^2
I_avg = (1/2)*3*10^8*8.854*10^-12*1000^2
I_avg = 1328.1 W/m^2
Now given that light is already polarized, So Using Malus's law, Intensity of light after passing through polarizer will be:
I1 = I_avg*(cosФ )^2
Ф = 30 deg, So
I1 = 1328.1*(cos 30 deg)^2 = 996.1 W/m^2
Now electric field corresponding to above Intensity will be:
I1 = (1/2)*c*e0*E1_max^2
E1_max = sqrt (2*I1/(c*e0))
E1_max = sqrt (2*996.1/(3*10^8*8.854*10^-12))
E1_max = 866 V/m
Answer:
It remains the same.
Explanation:
» At 100°C, it is the boiling point of water. And it starts changing from liquid state to gaseous state