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Aleksandr [31]
3 years ago
9

When Jacob bats a baseball with a net force of 4.719 N, it accelerates 33 m/s2. What is the mass of the baseball?

Physics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

its 24

Explanation:

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body starting from rest and moving with an uniform acceleration of 3 m/s²..What is its velocity after 15s?​
Luba_88 [7]
<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s\sf{ }

<h2>Given :</h2>

Initial velocity of body = 0 m/s

Acceleration of body = 3 m/s²

Time taken by body = 15 sec

<h2>To Calculate :</h2>

Final velocity of body = ?

<h2>How To Calculate ?</h2>

<h3>❒ </h3>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

<h3>❒</h3>

 To calculate the Final velocity of body we'll use the first equation of motion which says v = u + at

Where,

  • v is the Final velocity in m/s.

  • u is the Initial velocity in m/s.

  • a is the Acceleration in m/s².

  • t is the Time taken in second.

<h2>Calculation :</h2>

From first equation of motion

  • ⇒ v = u + at

  • ⇒ v = 0 + 3 × 15

  • ⇒ v = 0 + 45

  • ⇒ v = 45

Hence, the Final velocity of body is 45 m/s.

7 0
3 years ago
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A sprinter runs 200m west and 100 m east her displacement is
kykrilka [37]
100m so you will subtract 100m from 200m. and you will get your answer 200m-100m=100m
8 0
3 years ago
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Which three elements have strong magnetic properties?
lara [203]

Answer is A. Iron cobalt nickel

3 0
3 years ago
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The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you
katrin2010 [14]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The spring scale F_2 reads  F_2 =  2.4225 \ N

Explanation:

From the question we are told that

      The first force is  F_1  =  10.5 \ N

      The acceleration by which the cart moves to the right is  a = 2.50  \ m/s^2

      The mass of the cart is  m  = 3.231  kg

       

Generally the net force on the cart is  

       F_{net} = F_1 -  F_2

This net force is mathematically represented as

      F_{net} =  m * a

So  

        m*  a =  10 - F_2

        F_2 =  10.5 -  2.5 (3.231)

        F_2 =  2.4225 \ N

 

3 0
3 years ago
A 10 m long steel beam is accidentally dropped by a construction crane from a height of 4.89 m. The horizontal component of the
Otrada [13]

Answer:

e = 1.21 mV

Explanation:

given,                                

length of rod = 10 m                

height of drop = 4.89 m          

Earth’s magnetic field =  12.4 µT

acceleration of gravity = 9.8 m/s²

velocity of the beam                      

v = \sqrt{2gh}

v = \sqrt{2\times 9.8 \times 4.89}

v = 9.79 m/s                        

emf of the beam

e = B l v                              

e = 12.4 x 10⁻⁶ x 9.79 x 10

e = 1.21 x 10⁻³ V

e = 1.21 mV

4 0
3 years ago
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