You need to ask your teacher for any help and to evaluate and double check each step.
Depending on what type of triangle it is, for a right triangle you would use sin inverse=(opposite/hypotenuse), cos inverse=(adjacent/hypotenuse), or tan inverse=(opposite/adjacent). For any other triangle you would refer to the Law of sines where side a/sine of angle A=side b/sine of angle B and same goes for C
STEP 1- since 6 doesn't contain the variable to solve for move it to the right side of the equation by subtracting 6 from both sides
X^2-8X=-6
STEP 2- create a trinomial square on the left side of the equation find the value that is equal to the square of half of b the coefficient of x
(b/2)^2 =(-4)^2
STEP 3- add the term to each side of the equation
x^2-8x+(-4)^2=-6=(-4)
STEP 4- simplify the equation
x^2-8x+16=10
STEP 5- factor the perfect trinomial square into (x-4)^2
(x-4)^2=10
STEP 6-solve the equation for x
x=4= square root of 10
A. 4*1 - 3*2 = 4 - 6 = -2 (X
B. 4*4 - 3*2 = 16 - 6 = 10 (O
C. 4*7 - 3*6 = 28 - 18 = 10 (O
D. 4*4 - 3*(-3) = 16 + 9 = 25 (X
so the answers are B and C
The missing operations in order is division, division, subtraction, addition, addition, and division
