(A U B) = {1, 2, 3, 5, 8, 9}
(A U B)^c = {4, 6, 7}
A^c = {1, 4, 5, 6, 7 }
B^c = {4, 6, 7, 8, 9}
A^c ∩ B^c = {4, 6, 7}
8 + 3(4 + 5)
8 + 3(9)
8 + 27 = 35
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K, so, lets add them up
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21
1+2+3+4+5+6+7=28
etc
basically
all numbers 'x' such that
x=
and n is the set of all natural numbers
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21
1+2+3+4+5+6+7=28
etc
basically
all numbers 'x' such that
x=