Solving for <em>Angles</em>

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>

You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
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Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.
SA=2(lw+wh+lh) This is the formula for finding the surface area of a rectangular prism, where SA is surface area, l is length, w is width, and h is height.
208=2(lw+wh+lh)
104=lw+wh+lh Here, I divided both sides by 2 to get ride of the 2.
Now, I used prime factorization to find out all the prime factors of 104, which are 2, 2, 2, and 13. Since rectangular prisms only have 3 dimensions, I needed to combine two of the prime factors. In this case, I can either combine 2 of the 2s to get 2, 4, and 13 or I can combine 13 with one of the 2s to get 26, 2, and 2.
If my dimensions were 2, 4, and 13...
my surface area would be 172 sq cm.
If my dimensions were 2, 2, and 26...
my surface area would be 208 sq cm.
Hence, the width of the rectangular prism when the surface area is 208 square centimeters can be either 2 or 26.
In which point you want the value of x and y
If there's a constant value like k or c as well as x, then you have to set each equation equal to each other and plug in the restriction for x. So if x is less than or equal to 2, you plug in two! Then use algebra to solve for k or c!!