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3 years ago

Please help :D also like u have to write an expression

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

The answer should be 2n since there is n amount of side on the first polygon and twice as many in the second

professor190 [17]3 years ago

5 0

Https://kahoot.it/challenge/06610901?challenge-id=b1a4be66-6b3e-4f22-b8a3-1d33b623d952_1612379300076

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Determine if the point (12, 20) is on the graph of y = 2x – 5. Justify your answer.

Anna [14]

Answer:

456[67]98

Step-by-step explanation:

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3 years ago

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A line passes through the points (-2, 9) and (1, 3).

siniylev [52]

Answer:

slope = -2

y-intercept = 5

Step-by-step explanation:

1) Find slope:

$\frac{3-9}{1-(-2)}$ = $\frac{-6}{3}$ = -2

-2 = slope

2) Find y intercept trough point slope and slope-intercept forms

y - y1 = m (x - x1)

y - 9 = -2 (x + 2)

y - 9 = -2x -4

+ 9 + 9

y = -2x + 5

y = mx + b with b being the y-intercept

5 = y-intercept

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2 years ago

30 Points!! Vivian is at a fair in Coachella Valley, California. Much of the valley lies below sea level. Vivian has brought alo

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A positive number
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3 years ago

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a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

It is assumed that weight of pyramid is proportional to its volume.

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

Since, base and height of small pyramid and original pyramid are in proportion.

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

brainly.com/question/17950304

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2 years ago

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Solve the right triangle, ΔABC, for all the missing side and angles to the nearest tenth given sides a = 10.6 and b = 19.2.

Aliun [14]

Answer:

Part 1) $c=21.9\ units$

Part 2) $B=61.1\°$

Part 3) $A=28.9\°$

Part 4) $C=90\°$

Step-by-step explanation:

step 1

Find the length side c

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

substitute the given values

$c^{2}=10.6^{2}+19.2^{2}$

$c^{2}=481$

$c=21.9\ units$

step 2

Fin the measure of angle B

we know that

In the right triangle

$tan(B)=b/a$

substitute the given values

$tan(B)=19.2/10.6$

$B=arctan(19.2/10.6)=61.1\°$

step 3

Find the measure of angle A

we know that

The measure of interior angles in a triangle must be equal to 180 degrees

∠A+∠B+∠C=180°

Remember that in a right triangle the measure of angle C is 90 degrees

we have

$B=61.1\°$

$C=90\°$

substitute

$A+61.1\°+90\°=180\°$

$A=28.9\°$

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3 years ago