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lutik1710 [3]
2 years ago
8

Write the ratio for cosB

Mathematics
2 answers:
natima [27]2 years ago
4 0

Answer:

11/61

Step-by-step explanation:

cos b = adj side/hypotenuse

=11/61

gregori [183]2 years ago
4 0

Answer:

CosB = B/H

Base(B)= 11

Perpendicular (P)=60.

Hypotenuse (H)= 61

CosB = B/H

CosB= 11/61

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<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

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<u>Question 7</u>

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<u>Question 8</u>

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5) \overline{CD} \cong \overline{CD} (reflexive property)

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7) \angle ACD \cong \angle BCD (CPCTC)

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