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3 years ago

100/4 help please i need to know before tmr

Mathematics

2 answers:

algol [13]3 years ago

6 0

Are you asking what’s 100 divided by 4?

vovangra [49]3 years ago

5 0

Answer:25

Step-by-step explanation:

100 divided by 4 is 25 please mark brainliest.

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Over 5 days 5,385 people went to Chick-Fil-A. If the same amount of people went each day, how many people went on one day?

Naily [24]

Answer:

1077

Step-by-step explanation:

3 0

3 years ago

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Let theta be an angle in quadrant II such that cos theta = -2/3

Iteru [2.4K]

Answer:

So we have $\csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}$ .

Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given $\cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}})$ .

So to find the opposite we will just use the Pythagorean Theorem.

$a^2+b^2=c^2$

$(2)^2+b^2=(3)^2$

$4+b^2=9$

$b^2=5$

$b=\sqrt{5}$ This is the opposite side.

Now to find $\csc(\theta)$ and $\tan(\theta)$ .

$\csc(\theta)=\frac{\text{hypotenuse}}{\text{opposite}}=\frac{3}{\sqrt{5}}$ .

Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So $\csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}$ .

And now $\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}=\frac{\sqrt{5}}{-2}=\frac{-\sqrt{5}}{2}$ .

So we have $\csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}$ .

7 0

3 years ago

Read 2 more answers

Need help plz.......

Maru [420]

Answer:

oh I see. that's an interesting question but the problem is I hate maths

8 0

3 years ago

rounding me to the nearest hundred makes me 700.rounding me to the nearest ten nake me 740. the sum of my digit is 12.what numbe

yulyashka [42]

It 730 because when you round to the nearest ten its 740
So 10 more will make it 740

7 0

4 years ago

Find the inner product for (5,-1)*(-3,6) and state whether the vectors are perpendicular. a. 21; no c. -21; no b. 21; yes d. -21

nataly862011 [7]

Answer:

Step-by-step explanation:

If the dot product of the vectors is zero then they are perpendicular

(5, - 1) • (- 3, 6)

= (5 × - 3) + (- 1 × 6) = - 15 + (- 6) = - 15 - 6 = - 21 ≠ 0

Since product is not zero vectors are not perpendicular

7 0

4 years ago