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Alekssandra [29.7K]
3 years ago
8

Write the equation in standard form for the circle with center (-7,0) and radius 4 7

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

x² + y² - 8x -14y - 105 = 0

Step-by-step explanation:

The centre of the circle is (-7,0) and the radius is (4,7) . Firstly let's find the radius using Distance formula .

=> D = √{ (-7-4)²+(0-7)²}

=> D = √ 11² + 7²

=> D = √ 121 +49

=> D = √170

Now using the standard equation of circle ⭕ ,

=> ( x - h)²+(y-k)² = r²

=> ( x - 4)²+(y-7)²= (√170)²

=> x² + 16 -8x + y² + 49 -14y = 170

=> x² + y² -8x -14y = 170 -65

=> x² + y² - 8x -14y - 105 = 0

<h3>• Hence the equation of circle is x² + y² - 8x -14y - 105 = 0 .</h3>
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Answer:

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Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

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Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

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5+84=89

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10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

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