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ser-zykov [4K]
3 years ago
5

Is this right ? I need to know it’s due at 10:30

Biology
1 answer:
alex41 [277]3 years ago
6 0

yes, I think so......

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A geneticist discovers an obese mouse in his ca laboratory colony. he breeds this obese mouse with a normal mouse. all the f1 mi
inna [77]

The first geneticist has identified an obese allele that he or she believes to be recessive. We will define his or her allele as o1 and the normal allele as O1. The obese allele appears to be recessive based on the series of crosses he or she performed.

Cross 1 with possible genotype:  

 Obese (o1o1) × Normal (O1O1)  F1 All normal (O1o1)

Cross 2 with possible genotypes:

 F1 normal (Oo1) × F1 normal (O1o1)  F2 8 normal (O1O1 and O1o1)

       2 obese (o1o1)  

Cross 3 with possible genotypes:

 Obese (o1o1) × Obese (o1o1)  All Obese (o1o1)

 A second geneticist also finds an obese mouse in her colony and performs the same types of crosses, which indicate to her that the obese allele is recessive. We will define her obese allele as o2 and the normal allele as O2.

 The cross of obese mice between the two different laboratories produced only normal mice. These different alleles are both recessive. However, they are located at different gene loci. Essentially, the obese mice from the different labs have separate obesity genes that are independent of one another.

 The likely genotypes of the obese mice are as follows:

Obese mouse 1 (o1o1O2O2) × Obese mouse 2 (O1O1o2o2)  

 F1 All normal (O1o1O2o2)


8 0
3 years ago
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