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LuckyWell [14K]
3 years ago
13

Write the slope-intercept form of an equation of the line that passes through the given point and is perpendicular to the graph

of the equation. (-8,5) y = -4x +2
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

y = 1/4x + 7

Step-by-step explanation:

A perpendicular line will have an opposite reciprocal slope, so the slope will be 1/4

Plug in the given point and slope into y = mx + b, then solve for b

y = mx + b

5 = 1/4(-8) + b

5 = -2 + b

7 = b

Plug in b and the slope into y = mx + b

y = 1/4x + 7

So, the equation of the line is y = 1/4x + 7

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Marrrta [24]
Is this calculus or something?
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3 years ago
Sorry it’s messy, but if someone could help with a Step by Step
mezya [45]

Answer:

  a) 490

  b) 240

Step-by-step explanation:

b) It is convenient to answer part B first.

The number owning only a fax will be the number owning a fax less the number that own both a fax and a copier:

  420 -180 = 240 . . . . number owning only a fax

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a) The number owning one or the other will be the number owing a copier (which includes those owning both) plus the number owning only a fax:

  250 +240 = 490 . . . . number owning either

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If you want to work part A first, then you need to use the relation ...

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8 0
4 years ago
In March, Derrick had $25.50 in credit card debt.
Snezhnost [94]

Answer:

-20.50?

Step-by-step explanation:

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8 0
3 years ago
The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are
STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

<em>Let p = proportion of school dropouts rate</em>

SO, <u>Null Hypothesis,</u> H_0 : p = 0.081   {means that the proportion of dropouts has not changed from the historical value of 0.081}

<u>Alternate Hypothesis</u>, H_A : p \neq 0.081   {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of high school dropout rate = 6.5%

            n = sample of people = 1000

So, <u><em>test statistics</em></u>  =   \frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } } 

                               =  -2.05

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z < -2.05) = 1 - P(Z \leq 2.05)

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<em>Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

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3 years ago
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The cost with tax and coupon applied is $28.24
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3 years ago
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