To solve this problem you must apply the proccedure shown below:
1. You have that the <span>parabola is 12 meters high at the vertex and at a height of 10 meters, the width is 8 meter.
2. Therefore, you have:
x^2=-4a(y^2-k)
4</span>^2=-4a(10-12)
16=-40a+48
16=8a
a=16/8
a=2
y=0
x^2=-8(0-12)
x^2=96
x=√96
x=9.79x2
x=19.58
3. Therefore, as you can see, the answer is: 19.58 meters.<span>
</span>
Answer:
8.4 in
Step-by-step explanation:
Solution:-
- We consider the large right angle triangle namely, " XVW "
- We will recall all the trigonometric ratios that are applicable to all right angled triangles.
- While we are dealing with trigonometric ratios we have the following terms that needs to be correlated with the given specific problem:
Hypotenuse ( H ): Side opposite to 90 degrees angle
Base (B): The side adjacent to the available angle ( θ )
Perpendicular (P): The side opposite to the available angle ( θ )
- We will go ahead and mark our respective sides as follows:
Angle ( θ ) : 34°
Hypotenuse ( H ) : XW = 15 in
Base ( B ) : VW
Perpendicular ( P ) : VX
- Now recall all the trigonometric ratios studied:
sin ( θ ) = P / H = VX / XW
cos ( θ ) = B / H = VW / XW
tan ( θ ) = P / B = VX / VW
- Now choose the appropriate trigonometric ratio with two values given and one ( VX ) that needs to be determined as follows:
sin ( θ ) = P / H = VX / XW
sin ( 34° ) = VX / 15
VX = 15*sin ( 34° )
VX = 8.387 .. ( 8.4 ) in
(P+T)-7 = 6. 7 less than, meaning taking away 7 from the sum of (P + T) is as much as / equal to 6
(9/14)*6x = (27/7)x
And that is reduced by 10, then...
27/7x - 10
(8z - 10) ÷ (-2) + 5(z - 1) = 8z - 10 ÷ -2 + 5z - 5 = 8z + 5 + 5z - 5 = 13z
