Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (-4, -1)
Point (1, 4)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute [SF]:

- Add:

- Divide:

Answer:
A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct
Step-by-step explanation:
step 1
Find the area of the base of the rectangular pyramid
we know that
The volume of the rectangular pyramid is equal to

where
B is the area of the base
H is the height of the pyramid
we have


substitute and solve for B



step 2
Find the volume of the rectangular prism with the same base area and height
we know that
The volume of the rectangular prism is equal to

we have


substitute

therefore
The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct
<span>The graph of the equation is the set of all points that are solutions to the equation. The point (−6,7)(−6,7) is on the graph of the equation. True
</span><span>The graph of the equation is a single point representing one solution to the equation. not true
i 'm sorry idk the 3rd statement</span>
Answer:
The area of circle A is 16 times the area of circle B.
Step-by-step explanation:
he area of circle A is three times the area of circle B.
It depends on the value of π.
It depends on the actual diameters of the circles.
The area of circle A is 16 times the area of circle
the circumference of a circle = 2 x pi x r
Let imagine that the radius of B is 2cm
then the circumference of B = 2 x 2 x pi = 4pi
If the circumference of a is 4 times that of B, it means the circumference is 16 and the radius is 8
Area of a circle is pi x r^2
Area of B = pi x 2^2 = 4pi
Area of A = pi x 8^2 = 64pi
64/4 = 16 pi
I'm assuminng you want to find x and y
eliminate
hmm
eliminate y's
3 times 2=6
multiply first equation by 2 and 2nd by 3 and add
16x-6y=-32
<u>15x+6y=-123 +</u>
31x+0y=155
31x=155
divide both sides by 31
x=5
sub back
5x+2y=-41
5(5)+2y=-41
25+2y=-41
minus 25 both sides
2y=-66
divide by 2
y=-33
(x,y)
(5,-33)