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3 years ago

PLEASE HELP IMMEDIATELY

1 answer:

7 0

<span>The graph of the equation is the set of all points that are solutions to the equation. The point (−6,7)(−6,7) is on the graph of the equation. True
</span><span>The graph of the equation is a single point representing one solution to the equation. not true
i 'm sorry idk the 3rd statement</span>

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PLZ Hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!The sum of two numbers is 19 and their difference is 7, What are the two num

yuradex [85]

Answer:

13 and 6

Step-by-step explanation:

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3 years ago

Which Statement is true Tor the net and the Solla It WII Torm When It Is Tolueu?

pogonyaev

Idk what the answer is

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3 years ago

The sum of the digits of a two-digit number is 12. The number with the digits reversed is 15 times the original tens' digit. Fin

nika2105 [10]

$a-digit\ of\ tens\\b-digit\ of\ ones\\10a+b-the\ number\\10b+a-the\ number\ with\ reversed\ digits\\\\\left\{\begin{array}{ccc}a+b=12&\to b=12-a\\10b+a=15(10a+b)\end{array}\right\\\\\text{Substitute}\\\\10(12-a)+a=15(10a+12-a)\\10(12-a)+a=15(9a+12)\qquad\text{use distributive property}\\(10)(12)+(10)(-a)+a=(15)(9a)+(15)(12)\\120-10a+a=135a+180\\120-9a=135a+180\qquad\text{subtract 120 from both sides}\\-9a=135a+60\qquad\text{subtract 135a from both sides}\\-144a=60\qquad\text{divide both sides by (-144)}\\\\a=-\dfrac{60}{144}$

a is negative and it's not a digit.

<h3>Conclusion: Such a number does not exist.</h3>

8 0

3 years ago

The net weight in pounds of a packaged chemical herbicide is uniform for 49.62 < x < 50.04 pounds.

k0ka [10]

Answer:

a) $E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

b) $Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

c) $P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

Step-by-step explanation:

For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

$X \sim U(a= 49.62, b=50.04)$

Part a

For the uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

Part b

The variance for an uniform distribution is given by:

$Var(X)= \frac{(b-a)^2}{12}$

And if we replace we got:

$Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

Part c

For this case we want to find this probability:

$P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

6 0

4 years ago

Can someone help me with this math problem. what is the area

vovangra [49]

75•15=1125 (this is the area of the bottom rectangle)

10•25=250 (area of the top rectangle)

Now add those together to get the area of the WHOLE shape 250+1125=1375

7 0

3 years ago

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