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Inessa [10]
3 years ago
9

5.

Computers and Technology
1 answer:
larisa86 [58]3 years ago
3 0

Answer:

Explanation:

5 is correct answer

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Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn c
barxatty [35]

Answer:

#include <string>

#include <iostream>

using namespace std;

int main() {

string userInput;

getline(cin, userInput);

// Here, an integer variable is declared to find that the user entered string consist of word darn or not

int isPresent = userInput.find("darn");

if (isPresent > 0){

cout << "Censored" << endl;

// Solution starts here

else

{

cout << userInput << endl;

}

// End of solution

return 0;

}

// End of Program

The proposed solution added an else statement to the code

This will enable the program to print the userInput if userInput doesn't contain the word darn

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MrRissso [65]

Answer:

Explanation:

I  ....

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