Write a C++ program that produces a simple personalized adventure game called Lost Fortune about a band of explorers that finds
a stash of 750 gold pieces. Start by asking the player for the following information: the number of explorers and the number of explorers lost in battle. The program should then use the information input by the player (this information will be different EACH time the game is played) to generate and print a basic adventure story. Here’s a sample run of the input and output of the game (program) where the player entered the following input: 17 (for the number of explorers), followed by 13 (for the number of explorers lost).
1 answer:
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Answer:
Please kindly check explainations for the code.
Explanation:
lw $t1, Num1
lw $t2, Num2
lw $t3, Num3
blt $t1, $t2, if
beq $t1, $t2, elseif
else:
add $t0, $t3, 5
sw $t0, Result
endif:
#.....other statements after if-elseif-else
if:
sw $t1, Result
b endif
elseif:
ble $t2, $t3, if2
or $t0, $t1, $t3
sw $t0, Result
b endif
if2:
and $t0, $t2, $t3
sw $t0, Result
b endif
Go to attachment for the onscreen code.
Answer:
Explanation:
The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75
input_year = int(input())
if input_year % 4 == 0:
if input_year % 100 == 0:
if input_year % 400 == 0:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
else:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
