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kicyunya [14]
3 years ago
7

Bsinx%5E%7B2%7D%20%7D" id="TexFormula1" title="\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }" alt="\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                                     \displaystyle \lim_{x \to c} x = c

L'Hopital's Rule

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}

When we directly plug in <em>x</em> = 0, we see that we would have an indeterminate form:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle  \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}

Plugging in <em>x</em> = 0 again, we would get:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}

Substitute in <em>x</em> = 0 once more:

\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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trapecia [35]

Answer:

k = - 9

Step-by-step explanation:

h(x) = x² + 3

g(x) = x² - 6

g(x) = h(x) + k

x² - 6 = x² + 3 + k

-6 - 3 = k

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8 0
2 years ago
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A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so
mamaluj [8]

Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

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7 0
3 years ago
Five Questions FIFTY POINTS...look please don't just get this points I really need help in math rn. tysm for your help really ne
telo118 [61]

Answer:

1) 2 5/12

2) -3 1/30

3) 3/5

4) m = -28

5) b = -27

Step-by-step explanation:

1) You may be expected to solve this a different way, but how I prefer to solve these involves converting to "improper fractions", then making everything whole.

-11/3 = x - 5/4 (convert to improper fractions)

-44 = 12x - 15 (multiply everything by 12 to get whole numbers)

-29 = 12x (add 15 to both sides)

-29/12 = x (divide both sides by 12)

2 5/12 = x (convert to a mixed number, because that's what the question asks)

For clarity, that's two and five twelfths.

2) Same thing as above. I prefer improper fractions.

x + 17/6 = -1/5 (simplify and convert to improper fractions)

30x + 85 = -6 (multiply everything by 30 to get whole numbers)

30x = -91 (subtract 85 from both sides)

x = -91/30 (divide both sides by 30

x = -3 1/30 (convert to a mixed number, because that's what the question asks)

For clarity, thats minus/negative three and one thirtieth.

3) Same thing as above.

-(11/3)x = -11/5

-55x = -33

55x = 33

x = 33/55

x = 3/5

4) Same as above, but it's multiple choice! Yay!

-3m = 84

m = -28

5) You know the drill.

-b = 27

b = -27

I'd be happy to explain more if you need it at all. I'd recommend that next time this comes up, you post just one problem and see if you can understand the method so you can better learn how to do it on your own. Good luck (:

8 0
2 years ago
The sum of the digits of a two-digit number is 5. If the number is multiplied by 3, the result is 42. Write and solve a system o
Elenna [48]
A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

"The sum of the digits is 5"
x + y = 5

The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

The number is: 10x + y
3(10x + y) = 42

The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42

Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1

then plug x = 1 into either equation to find y

1 + y = 5
y = 4

remember the x and y represent digits so the number xy is 14
6 0
3 years ago
Please help me with this assignment ASAP!!! I only partially understand, so please explain. Also it's a work sample.
Rudiy27
To find the answer, we can first find the distance each of them have, then divide it by their speed to find the time needed.

Distance Steve need to travel: 300 feet
Distance Paula need to travel:
300+175(behind steve) = 475 feet

Time needed respectively:

Steve: 300 ÷ 9 = 33.33.. seconds
Paula: 475 ÷ 15 = 31.66... seconds

As we can see from the result, Paula would take less time to reach the goal (31.66<33.33),
therefore, Paula win the bike race by:

33.33-31.67
=1.66...
≈1.67 feet

Thus Paula won by 1.67 feet.

Hope it helps!
5 0
2 years ago
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