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3 years ago

Can some one plz tell me the answer

Mathematics

1 answer:

madreJ [45]3 years ago

4 0

Answer:

h=15 cm. is the answer for this question

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The rectangle below has an area of x^2-4x-12x 2 −4x−12x, squared, minus, 4, x, minus, 12 square meters and a length of x+2x+2x,

solniwko [45]

Answer:

Width = x-6 metres

Step-by-step explanation:

The formula for the area of a rectangle is represented by Length (l) × Width (w).

If the area is x^2-4x -12, which is an algebraic expression, The best way to find its length and breadth which would be a product of themselves is by FACTORIZATION.

To factorize x^2-4x -12, we say:

×^2 = a, -4x = b, -12 = c

Product: a×c; -12 × x^2= -12x^2

Sum: b; -4x derived by saying (-6x+2x)

Note that the expression of the sum (-6x+2x) must be able to be multiplied to give product (-12x^2).

Hence, we rewrite our algebraic expression using the sum expression.

x2 - 6x + 2x - 12

We then factorize by using a common factor (x and 2)

x( x - 6) + 2 (x - 6)

(x+2) (x-6)

Thus, the factors are x+2 and x-6

This means that (x+2) and (x-6) will be multiplied to give x^2-4x-12. Therefore, if x+2 metres is the Length, x-6 metres is the width.

6 0

4 years ago

Read 2 more answers

What is 21 divided by 1/3?

pshichka [43]

$\frac { 21 }{ \frac { 1 }{ 3 } } \\ \\ =\frac { 21 }{ 1 } \cdot \frac { 3 }{ 1 } \\ \\ =63$

6 0

3 years ago

Read 2 more answers

Please help thx ______________

lubasha [3.4K]

Answer:

She drew a rectangle

Step-by-step explanation:

Rectangles have four right angles, and two pairs of (opposite) congruent sides.

7 0

4 years ago

Read 2 more answers

ANSWER FAST ILL GIVE BRAINLIEST!!

Dominik [7]

Given:

A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.

To find:

The surface area of the pyramid to the nearest whole number.

Solution:

A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.

Area of a square is

$A_1=(edge)^2$

$A_1=(10)^2$

$A_1=100$

So, area of square base is 100 sq. in.

Area of a triangle is

$A_2=\dfrac{1}{2}\times base\times height$

$A_2=\dfrac{1}{2}\times 10\times 4$

$A_2=20$

So, area of each triangular surface is 20 sq. in.

Now, the total surface area of the pyramid is

Total area = Area of square base + Area of 4 congruent triangles.

$A=A_1+4\times A_2$

$A=100+4\times 20$

$A=100+80$

$A=180$

Therefore, the area of the pyramid is 180 sq. in.

5 0

3 years ago

I need help with this question

aev [14]

Answer:

9 UNITS 2

Step-by-step explanation:

9 UNITS 2

8 0

4 years ago