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castortr0y [4]
3 years ago
15

PLEASE HURRY 3 MINUTES LEFT

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

Step-by-step explanation:

-180 i think not 100%

Georgia [21]3 years ago
6 0
Guacamole ninja penice
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The markup of an MP3 player is $207.20. The markup rate is 60%. What is the cost?
Kipish [7]
345.3 
correct me if im wrong
7 0
3 years ago
Compare 8^0 and 8^-2. which is greater? Explain your reasoning.
aev [14]

Hello there!

8^0 amd 8^-2


Let me start with 8^-2

8^-2 = 1/8 * 8

8^-2 = 1/64

which equals to 0.015625 in decimal


8^ 0 =  1

Yep, that's the answer! Easy, isn't? Well you may have been wondering why 8^0 is equal to 1.

I quoted an explanation online that says:    Think of "multiplication" as always including an extra "1" as a multiplier.

So it'd be like

8^ 0

8/8 = 1


Remember: Whenever a number has an exponent 0, the answer MUST be 1.


Thus,

8^0 is greater. As you can see, it is equal to 1, while the other one is equal to 0.01


I'm terrible at explaining stuff. I hope you find this answer somehow helpful :)

4 0
4 years ago
Read 2 more answers
Multiply (2.5x10^-10) (7x10^-6)
serious [3.7K]
We want to multiply 2.5\cdot10^{-10} by 7\cdot10^{-6}.

The numbers are written in scientific notation. So we expect the answer also to be in scientific notation.

the multiplication of the 10's, using the exponents rule is :

10^{-10}\cdot 10^{-6}=10^{-10+(-6)}=10^{-10-6}=10^{-16}

the multiplication of the other 2 numbers is:

2.5\cdot7=17.5=1.75\cdot10

(we write the number so that it has only one digit to the left of the decimal point).

Thus, 

(2.5\cdot10^{-10})\cdot(7\cdot10^{-6})=1.75\cdot10\cdot10^{-16}=1.75\cdot10^{-15}



Answer: 1.75\cdot10^{-15}


6 0
4 years ago
Read 2 more answers
The distance of an object thrown upward is modeled by the equation h=-2x^2+3t+4, where h is the height of the object in feet at
kipiarov [429]

So for this, we will have to find the zeros (x-intercepts) of the equation. In this case, we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} (a = x^2 coefficient, b = x coefficient, c = constant). Using our info, our equation is such: x=\frac{-3+\sqrt{3^2-4*(-16)*4}}{2*(-16)},\frac{-3-\sqrt{3^2-4*(-16)*4}}{2*(-16)}

Firstly, solve the multiplications and the exponents: x=\frac{-3+\sqrt{9+256}}{-32},\frac{-3-\sqrt{9+256}}{-32}

Next, do the addition: x=\frac{-3+\sqrt{265}}{-32},\frac{-3-\sqrt{265}}{-32}

Next, plug in the equations into the calculator and your answer will be: x=-0.41,0.60

Since we can't have negative time in this situation, it can't be -0.41 seconds. Which means that the object is visible for about 0.60 seconds, or C.

8 0
4 years ago
Which is the correct description of how to find the volume of a cylinder?
sertanlavr [38]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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