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uysha [10]
4 years ago
14

Compare 8^0 and 8^-2. which is greater? Explain your reasoning.

Mathematics
2 answers:
labwork [276]4 years ago
8 0
<h3>Hey there!</h3><h3>8^0 = 1</h3><h3>8^{-2} = \frac{1}{64} = 0.015625</h3><h3>8^0 > 8^{-2}</h3><h3>The bigger one is (answer) : 8^0</h3><h3>Reason: Exponents with Negatives are usually decimals/ fractions, which are UNDERNEATH   0 and usually exponents with Positives  are usually ABOVE   0</h3><h3>Good luck on your assignment and enjoy your day!  </h3><h3>~LoveYourselfFirst:)</h3>
aev [14]4 years ago
4 0

Hello there!

8^0 amd 8^-2


Let me start with 8^-2

8^-2 = 1/8 * 8

8^-2 = 1/64

which equals to 0.015625 in decimal


8^ 0 =  1

Yep, that's the answer! Easy, isn't? Well you may have been wondering why 8^0 is equal to 1.

I quoted an explanation online that says:    Think of "multiplication" as always including an extra "1" as a multiplier.

So it'd be like

8^ 0

8/8 = 1


Remember: Whenever a number has an exponent 0, the answer MUST be 1.


Thus,

8^0 is greater. As you can see, it is equal to 1, while the other one is equal to 0.01


I'm terrible at explaining stuff. I hope you find this answer somehow helpful :)

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Explanation:
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Given:  
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" (x² + 4x + 8) (2x − 1) "  ;  Find the product: 

↔  " (2x − 1) (x² + 4x + 8) "  ; 
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Note:  " (a + b) (c + d + e) = ab + ad + ae + bc + bd + ae " .
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  →  " (2x − 1) (x² + 4x + 8) = 

      (2x * x²) + (2x * 4x) + (2x *8)  + (-1 * x²) + (-1 * 4x) + (-1 * 8) ; 

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=     2x³ + 8x² + 16x − x² − 4x − 8) ; 

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And rewrite the expression:
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   →  " 2x³  +  7x² + 12x − 8 " ;

   → which is:  Answer choice:  [A]:  " 2x³  +  7x² + 12x − 8 " .
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3 years ago
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Really hope this helps :)

           

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