Required area of shaded portion
= Area of square ABCD - 4 × area of one quadrant
= Area of square ABCD - 4 × area of one quadrant
Find the 8th term of the geometric sequence 10, -40, 160, ...
2 answers:
You might be interested in
Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
The characteristic equation is
so the characteristic solution is
For the particular solution, we can try looking for a solution of the form
Substituting into the ODE, we have
So the general solution to the ODE is