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lyudmila [28]
3 years ago
12

Find the 8th term of the geometric sequence 10, -40, 160, ...

Mathematics
2 answers:
mart [117]3 years ago
3 0

Answer:

-163840

Step-by-step explanation:

Bas_tet [7]3 years ago
3 0
-163840 dirnnenemwfiire
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Please help me with this question ASAP
valentina_108 [34]

Answer:

volume \:  =  \:  \frac{1}{2}  \times 6 \times 7 \times 16 \\  = 896

Hope it helps

5 0
3 years ago
Eight more than five times a number is negative 62.
lys-0071 [83]

5n+8 =-62

subtract 8 from each side

5n = -70

divide by 5

n = -14

5 0
3 years ago
How many solutions are there to the equation below? |x| = -31​
ella [17]

Break down the problem into these two equations;

x = -31

-x = -31

Solve for the 1st equation; x = -31

x = -31

Solve for the 2nd equation; -x = -31

x = 31

Collect all solutions

x = ±31

Check the solution

When x = -31, the original equation; |x| = -31 does not hold true. Thus, we will drop x = -31 from the solution set.

Check the solution again;

When x = 31, the original equation |x| = -31 does not hold true as well. Thus we will drop x = 31 from the solution set.

Therefore,

<u>No solution exists to this equation. </u>

5 0
3 years ago
Read 2 more answers
Can someone help me
sergij07 [2.7K]

Answer:

1)  (c)∠ G = 34°

2) (a)  x = 33°

3) (d) The perpendicular segments are  JM, KL, PQ AND NR.

Step-by-step explanation:

Here in the given questions:

1)  p II r

⇒ ∠ G  = 34°  (ALTERNATE EXTERIOR ANGLES)

Hence, the measure of  ∠ G = 34°

2) In the given triangle:

The measure of exterior angle is always the sum of interior opposite angles.

⇒ Here, x + 72°  = 105°

or, x = 105° - 72° =   33°   , or x = 33°

3) The given plane in the cube is JKPN

The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.

Hence, the segments are  JM, KL, PQ AND NR.

7 0
3 years ago
In the following table of values, the first differences are
ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

d = y_{n+1} - y_n

So, we have:

d = y_2 - y_1 = 27 - 34 = -7

d = y_3 - y_2 = 20 - 27 = -7

d = y_4 - y_3 = 13 - 20 = -7

d = y_5 - y_4 = 6-13 = -7

<em>Hence, the first differences are -7 (all through)</em>

5 0
3 years ago
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