Answer:
Yes, they are congruent by either ASA or AAS.
Step-by-step explanation:
google lol
The answer is 28 for the volume
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
9 weeks
Step-by-Step Instructions:
Step 1: State what is know
Bart deposits 10 dollars every week
Bart has 90 dollars in his account
Step 2: Find a way to solve for how many weeks Bart ha been depositing money
Total money in account / 10 dollars deposit per week = weeks he has been depositing
Step 3: Substitute in values and solve
90/ 10 = 9
Step 4: State your findings
Therefore Bart has been depositing money for 9 weeks
Answer:
{y≥1
,{y-x>0
Step-by-step explanation:
First of all you have to consider the shaded region. It is bound by two lines.
The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.
the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is
y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0
y=x if we subtract x from both sides we have
y-x=0
since the shaded region is on the upper side as y-x increases the in equality will be
y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.