1.Identify the mistake in the problem below. Then, correct the mistake.

A university planner wants to determine the proportion of spring semester students who will attend summer school. Suppose the un

ss7ja [257]

Answer:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior estimation for the population proportion we can use the value $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.112}{1.64})^2}=53.60$

And rounded up we have that n=54

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.112$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior estimation for the population proportion we can use the value $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.112}{1.64})^2}=53.60$

And rounded up we have that n=54

3 0

3 years ago

0.97 in word formation

stepan [7]

Answer:

97 hundreths or 97 cents

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Six Pepperidge Farm bagels were weighed, yielding the following data (grams):

ratelena [41]

Answer:

A) Average weight = 112.97

standard deviation = 3.913

B) 119.4069

Step-by-step explanation:

A) Estimate the true average weight and standard deviation of the weight

attached below is a detailed solution

Average weight = 112.97

standard deviation = 3.913

B) Assuming a normal distribution Estimate the weight below

attached below is a detailed solution

= 119.4069

6 0

3 years ago

grigory [225]

For this case, what we must do is find the scale factor.
We have then that the scale factor is given by:
$k = \frac{L1}{L2}$
Where,
L1: side length of polygon ABCD
L2: side length of polygon PQRS
Note: both sides belong to the same side of each polygon
Substituting the values we have:
$k = \frac{6}{12}$
Rewriting we have:
$k = \frac{1}{2}$
Answer:
The scale factor of dilation is given by:
$k = \frac{1}{2}$

3 0

3 years ago

Read 2 more answers

Find the area, in square feet, of a triangle whose base is 42⁄3 feet and whose altitude is 84⁄7 feet. A. 135⁄21 B. 20 C. 40 D. 2

CaHeK987 [17]

Answer:

Option B. $20\ ft^{2}$