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salantis [7]
3 years ago
7

HELPPPPP ASAPPPP

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the  time, in seconds, after that ball was set :

h(t)=-16t^2+20t+6 ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put \dfrac{dh}{dt}=0

Now put t = 0.625 in equation (1)

h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}

So, the maximum height of the volleyball is 12.25 feet.

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adelina 88 [10]
<h2>Hello!</h2>

The answer is: The correct dose of medication to give is 5.6 mL

<h2>Why?</h2>

To solve this problem we need to establish a relationship between the prescripted medication and the available solution.

Let's write the needed equations to establish the relantionship:

\frac{125mg}{5mL}=1\\\\125mg=5mL

The available solution means 125 mg each 5 mL of solution, so:

\frac{125mg}{5mL}=\frac{140mg}{x}\\\\x*\frac{125mg}{5mL}=140mg\\\\x=140mg*\frac{5ml}{125mg}=\frac{700mg*mL}{125mg}=5.6mL

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Have a nice day!

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Step-by-step explanation

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Hey!

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Answer:

Step-by-step explanation:

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