Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
4 candles
Step-by-step explanation:
x = amount of candles
use the equation: $24.75 X = $100
Answer:
4.02m
Step-by-step explanation:
carry 1 1
1 . 2 8
+ 2 . 7 4
4 . 0 2
just add the two given numbers
6 and 10 because 6 times 10 is 60 and 6 plus 6 plus 20 plus 10 is 32
Answer:
Ok
Step-by-step explanation:
Thanks that was inspiring