Whats 195÷13 using base-ten blocks????

Arbara sells iced tea for $1.49 per bottle and water for $1.25 per bottle. She wrote an equation to find the number of drinks sh

pashok25 [27]

If ice tea is lets say y (ice tea = y) and water is x (water = x) then the answer is
1.25x + 1.49y = 100
the error is that she forgot the second variable(y).

8 0

2 years ago

If matrix A is of the size 2×3 and we are able to add matrix B to A. what must be the size of B be?

tankabanditka [31]

Answer:

6 be because 2×3 =6 so B it will be the given answer

5 0

2 years ago

What are the factors of 13m-2n

Lelechka [254]

<span>the first term 13m has TWO factors 13 and m
the second term 2n has TWO factors 2 and n</span>

3 0

3 years ago

Read 2 more answers

Another one help please

guapka [62]

there must be subtraction of multiplication of each two diagonal,

|G|=[12×2-(-6)×0]

=(24+0)

=24ans

8 0

3 years ago

Read 2 more answers

According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random

Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.39, n = 100$

Then

$s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488$

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

5 0

2 years ago