18/90
Divide by the common factor of 18 and 90, 9.
(18/9) / (90/9)
2/10
Divide top and bottom by 2
1/5
Hope this helps :)
Answer:
193.53 miles
Step-by-step explanation:
Please see the diagram for understanding of how the angles were derived,
Applying Alternate Angles, ABO =77 degrees
The bearing from B to C is 192=180+12 degrees
Subtracting 12 from 77, we obtain the angle at B as 65 degrees.
We want to determine the boat's distance from its starting point.
In the diagram, this is the line AC.
Applying Law of Cosines:

The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).
Answer:
VW=36
VT=27
Step-by-step explanation:
VW is the midsegment of the triangle
so
VW=72/2
=36
VXT is a right angle triangle
so
a²+b²=c²
a=√c²-b²
a=√45²-36²
a=√(45-36)(45+36)
a=√9×81
a=√9×√81
a=27
therefore
VT=27