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3 years ago

13

If Sally bought some flowers and she was charged $41.75 and the state of Virginia charged her $2.55 for tax, what was the cost o

f the flowers?

2 answers:

STALIN [3.7K]3 years ago

5 0

Answer:

39.20

Step-by-step explanation:

simply subtract

madreJ [45]3 years ago

5 0

41.75 - 2.55 = 39.2

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What's the answer?????????????

Taya2010 [7]

Answer:

BD = 12 :)

Step-by-step explanation:

Alright, we'll need the Pythagorean theorem for this!

So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)

DC = 5

We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:

BD^2 + DC^2 = BC^2

BD^2 + 5^2 = 13^2

BD^2 + 25 = 169

BD^2 = 169 - 25 = 144

BD = √144 = 12 :)

3 0

4 years ago

On a test, Shane answered 37 out of 40 questions correctly . What portion of his answers was correct

nikitadnepr [17]

37x2= 74
37/2=18.5
74+18.5=92.5
93%

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3 years ago

The state where you live has a 6% sales tax. If you purchase a car for $9,800, what will you pay, including tax? (this is a two-

mestny [16]

Answer: $10,388

Step-by-step explanation:

The first step is to calculate the tax for the car:

$9,800*0.06=588$

The second step is to add the price of the car and the corresponding tax:

$9,800+588=10,388$

So, you will pay $10,388.

5 0

3 years ago

A machine can scan 12 pages in 3/5 minutes how many pages in 1 minutes

natali 33 [55]

2.2to 4 pages in a minute because 12 divided by 3 is 4 and 12 divided by 5 is 2.2

6 0

3 years ago

Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

bekas [8.4K]

Answer:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

$p(A) = \frac{5}{7}$

$p(B) = \frac{2}{3}$

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

And for this special case we want to find this probability:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

7 0

3 years ago