Answer:
- Diploid → Prophase, metaphase, and anaphase
- Haploid → Telophase
Explanation:
During prophase I, chromosomes get condensed. Each of the chromosomes gets in pair with its homologous one. They do so to make the crossing-over possible, a stage where they interchange their parts → 2n
During metaphase I, each of the homologous pairs is driven to the equatorial plane, where they randomly line up → 2n
During anaphase I, occurs the independent separation of homologous chromosomes that migrate to opposite poles of the cell. This separation generates different chromosomal combinations in the daughter cells. There are two alternatives per homologous pair → 2n
In telophase I, half of the chromosomes are already in one of the poles, while the other half is on the other pole. Each group of chromosomes has now half the number of the original cell. The nuclear membrane forms again in each pole → n
Finally, occurs cytokinesis, which involves the invagination of the cell membrane and cytoplasmic division.
The two new cells are ready for meiosis II.
Answer: peptide bonds
Explanation: I think that's the answer.
The movement of matter across a cell membrane against a concentration difference is called an Active Transport.
There are 3 main processes in urine formation. These are Filtration, reabsorption and secretion.
Filtration
Blood enters the afferent arteriole and goes to glomerulus where blood is filtered and it will sip inside the glomerulus and nonfilterable components will go into efferent arteriole.
Reabsoprtion
Molecules and ions will be reabsrobed into the system. The fluid will pass into the proximal, distal and convoluted tubules, loop of henle, as water an ions are removed as the fluid osmolarty changes. Last is secretion of substance that is not filtered.
Answer:
I think the answer is parent one has to dominant off string since it looks more like them since they might they might have better geans
