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Gennadij [26K]
2 years ago
5

Tyler swims at a constant speed of 10 meters every 20 seconds. Use a unit rate to figure out how long it will take him to swim 1

50 meters.
Put a box around the unit rate when you show your work in the box on the left.

Type how long it will take him to swim 150 meters in the box on the right.
Mathematics
1 answer:
crimeas [40]2 years ago
7 0

Answer:

s=d/t

=10/20=1/2

d=150

s=1/2

t=d/s

t=150/1/2

t=150/2

t=70

Step-by-step explanation:

okay?need thanks

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ST | PR. Find QR. 35 28 40
Greeley [361]

Answer:

The answer is 47

Step-by-step explanation:

I'm pretty sure this is the answer :)

40 - 28 = 12

35 + 12 = 47

Proof: 35 - 28 = 7

          47 - 40 = 7

8 0
2 years ago
Num supermercado, 200g de queijo e 300g de presunto custam juntos R$ 9,00. Renan resolveu comprar 400g de queijo e 400g de presu
nikklg [1K]
The answer to this question is d
7 0
3 years ago
A rectangle that is 11.2 inches by 8 inches. The scale in the plan is 4in:5ft find the length and width or the actual studio. Fi
leonid [27]

Answer:

l=14\,ft\,\,\,\,w=10\,ft\\\\Area\,\,of\,\,actual\,\,studio=140\,ft^2\\\\

Step-by-step explanation:

As we know 1 ft has 12 inches.

scale\,\,in\,\,the\,\,plan=\frac{5\,ft}{4\, in}\\

We can find the length and width of studio by multiplying rectangle parameters with scale.

l=11.2\,in\times \frac{5\,ft}{4\,in}\\\\l=14\,ft\\\\w=8\,in \times \frac{5\,ft}{4\,in}\\ \\w=10 \,ft\\\\Area\,\,of\,\,actual\,\,studio=14\times 10=140\,ft^2\\

5 0
3 years ago
Line Segment DE is parallel to side BC of right triangle ABC. CD = 3, DE = 6, and EB = 4. Compute the area of quadrilateral BCDE
dybincka [34]

The area of quadrilateral BCDE = 20.4 sq. units

Let AD = x and AE = y.

Since ΔABC and ΔAED are similar right angled triangles, we have that

AC/AD = AB/AE

AC = AD + CD

= x + 3.

Also, AB = AE + EB

= y + 4

So, AC/AD = AB/AE

(x + 3)/x = (y + 4)/y

Cross-multiplying, we have

y(x + 3) = x(y + 4)

Expanding the brackets, we have

xy + 3y = xy + 4x

3y = 4x

y = 4x/3

In ΔAED, AD² + AE² = DE².

So, x² + y² = 6²

Substituting y = 4x/3 into the equation, we have

x² + y² = 6²

x² + (4x/3)² = 6²

x² + 16x²/9 = 36

(9x² + 16x²)/9 = 36

25x²/9 = 36

Multiplying both sides by 9/25, we have

x² = 36 × 9/25

Taking square root of both sides, we have

x = √(36 × 9/25)

x = 6 × 3/5

x = 18/5

x = 3.6

Since y = 4x/3,

Substituting x into the equation, we have

y = 4 × 3.6/3

y = 4.8

To find the area of quadrilateral BCDE, we subtract the area of ΔAED from area of ΔABC.

So, area of quadrilateral BCDE = area of ΔABC - area of ΔAED

area of ΔABC = 1/2 AC × AB

= 1/2 (x + 3)(y + 4)

= 1/2(3.6 + 3)(4.8 + 4)

= 1/2 × (6.6)(8.8)

= 1/2 × 58.08

= 29.04  square units

area of ΔAED = 1/2 AD × AE

= 1/2xy

= 1/2 × 3.6 × 4.8

= 1/2 × 17.28

= 8.64 square units

area of quadrilateral BCDE = area of ΔABC - area of ΔAED

area of quadrilateral BCDE = 29.04 sq units - 8.64 sq units

area of quadrilateral BCDE = 20.4 sq. units

So, the area of quadrilateral BCDE = 20.4 sq. units

Learn more about area of a quadrilateral here:

brainly.com/question/19678935

4 0
2 years ago
Factor this trinomial completely.<br> 2x^2 + 6x + 4
Dmitrij [34]

Step-by-step explanation:

2 {x}^{2}  + 6x + 4 \\  \\  = 2 {x}^{2}  + 2x + 4x + 4 \\  \\  = 2x(x + 1) + 4(x + 1) \\  \\  = (2x + 4)(x + 1) \\  \\  = 2(x + 2)(x + 1) \\  \\  = 2(x + 1)(x + 2) \\ are \: the \: required \: factors \: of \: the \:  \\ given \: trinomial

5 0
3 years ago
Read 2 more answers
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