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3 years ago

Most intruments produce notes across ranges called octaves which are made up of 8 notes how many octaves do 51 notes span?

Mathematics

1 answer:

mojhsa [17]3 years ago

8 0

Answer: 51 notes span 6 octaves.

Step-by-step explanation:

The word "octave" is a Latin word that means "eight".

In an instrument, Each octave is made up of 8 musical notes.

If we have 51 notes , the number of octaves can be made in it = $\dfrac{51}{8}$

$=6.375\approx6\ \ \ \ \ \text{[Rounded to the nearest whole number]}$

Hence, 51 notes span 6 octaves.

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Round this number to the given place values:

nataly862011 [7]

Answer:

Ones place: 456.3000

tenths place: 456.3000

hundredths place: 456.2990

thousandths place: 456.2991

5 0

3 years ago

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when $X = 59.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59.5 - 56}{1.12}$

$Z = 3.1$

$Z = 3.1$ has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0

3 years ago

An assistant cook peeled 18 potatoes in 6 minutes. At this rate, how many potatoes can he peel in 50 minutes?

malfutka [58]

Answer:

$150$ potatoes

Step-by-step explanation:

Since the assistant can peel $18$ potatoes in $6$ minutes, we know that he can peel $\frac{18}{6}=3$ potatoes in $1$ minute. Therefore, he will be able to peel $3*50=150$ potatoes in $50$ minutes. Hope this helps!