What is the derivative of sqrt7 times x +sqrt2x

1 answer:

4 0

I guess you mean the derivative of:

√7x + √2x, if so then:

Remember that the derivative of √u = 1/(2√u) . u'

if 7x = u, then u' = 7 , hence the derivative of √7x is 7/(2√7x)
Use same logic for √2x and you will find:

y' = 7/(2√7x) + x/√2x

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