What is the derivative of sqrt7 times x +sqrt2x

1 answer:

4 0

I guess you mean the derivative of:

√7x + √2x, if so then:

Remember that the derivative of √u = 1/(2√u) . u'

if 7x = u, then u' = 7 , hence the derivative of √7x is 7/(2√7x)
Use same logic for √2x and you will find:

y' = 7/(2√7x) + x/√2x

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Jackson is playing a game of chance where he must randomly draw a marble out of a jar. He calculates the probability of drawing

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Using complementary events, considering a $\frac{1}{4}$ probability of drawing a red marble, the probability of not drawing a red marble is of $\frac{3}{4}$ .

<h3>What are complementary events?</h3>

They are mutually exclusive events which have the sum of their probabilities as 1.

In this problem, we consider that there is a $\frac{1}{4}$ probability of drawing a red marble, and since drawing a red marble and drawing a non-red marble are complementary events, we have that:

$\frac{1}{4} + p = 1$