3 years ago

Solve (2x-1)^2=8 using the quadratic formula

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Step-by-step explanation:

The given equation is :

$(2x-1)^2=8$

$(2x-1)=\sqrt{8}\\\\2x-1=\pm 2\sqrt2\\\\2x=\pm 2\sqrt2 +1\\\\x=\dfrac{2\sqrt2 +1}{2}\\\\x=\pm (\sqrt 2+\dfrac{1}{2})\\\\or\\\\x=\sqrt2+\dfrac{1}{2},-\sqrt2-\dfrac{1}{2}$

Hence, this is the required solution.

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Hi!

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