Answer:
-7
Step-by-step explanation:
Hope it helped!
The slope is 2.
The slope is 1/2.
The y intercept is 4.
The y intercept is 8
The points (-2,-5) and (8,0) are also on the line
The points (-5,-2) and (1,10) are also in the line.
Answer:
a. 1 1/2 (or 3/2)
b. 2/3
c. 1
d. 1
Step-by-step explanation:
Part A: (1,1) (7,5)
To determine the slope, you will use the equation m=(y2-y1)/(x2-x1). Keep in mind that it doesn't matter what point you use for (x1, y1) or (x2, y2).
Let's plug in the numbers for part a:
m=(7-1)/(5-1)
Let's then solve the problems inside the parentheses:
m=6/4
And finally, we simplify:
m=3/2 (or 1 1/2 depending on what your teacher wants for an answer)
For these others, I will just go through the steps and not explain them, if you need help or don't understand something I'm doing, either look back at what I did for part a or comment on this answer.
Part B: (1,1) (5,7)
m=(5-1)/(7-1)
m=(4/6)
m=2/3
Part C: (2,5) (-1,2)
m=(-1-2)/(2-5)
m=(-3/-3)
m=1
Part D: (2,5) (-7,-4)
m=(-7-2)/(-4-5)
m=(-9/-9)
m=1
Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
