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3 years ago

Try to graph y=0.4 x

Mathematics

2 answers:

Vlad [161]3 years ago

6 0

Answer: y = 0.4x in desmos

Step-by-step explanation:

Firdavs [7]3 years ago

6 0

Answer:

Not applicable.

Step-by-step explanation:

You could use Desmos as another person answered. However, if you are graphing by hand, simply choose two points and draw a straight line between them.

For example, you could pick x = 0 and x = 1. This gives you the two points (0, 0) and (1, 0.4)

Plot those two points and use a straight edge to draw a line between the two.

In case you are having trouble plotting (1, 0.4) since it is a decimal, try setting x = 5, you will get (5, 2) which should be much easier to graph.

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I need help on this!

castortr0y [4]

Answer:

The answer would be B

Step-by-step explanation:

The answer would be B because if you divide 24 ÷ by 3.5 it equals 6.86. . .

So therefore (24 ÷ 3.5 = 6.86)

I hope my answer helped you!!!!

3 0

4 years ago

Read 2 more answers

What is the total resistance of a parallel circuit that has three loads? Load one has a resistance of 6 ohms. Load two has a res

gizmo_the_mogwai [7]

Answer:

The total resistance of these three resistors connected in parallel is $1.7143\Omega$

Step-by-step explanation:

The attached image has the circuit for finding the total resistance. The circuit is composed by a voltage source and three resistors connected in parallel: $R_1=6\Omega$ , $R_2=3\Omega$ and $R_3=12\Omega$ .

<u>First step: to find the source current</u>

The current that the source provides is the sum of the current that each resistor consumes. Keep in mind that the voltage is the same for the three resistors ( $R_1$ , $R_2$ and $R_3$ ).

$I_{R_1}=\frac{V_S}{R_1}$

$I_{R_2}=\frac{V_S}{R_2}$

$I_{R_3}=\frac{V_S}{R_3}$

The total current is:

$I_S=I_{R_1}+I_{R_2}+I_{R_3}=\frac{V_S}{R_1}+\frac{V_S}{R_2}+\frac{V_S}{R_3}=\frac{R_2\cdot R_3 \cdot V_S+R_1\cdot R_3 \cdot V_S+R_1\cdot R_2 \cdot V_S}{R_1\cdot R_2\cdot R_3}$

$I_S=V_S\cdot \frac{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}{R_1\cdot R_2\cdot R_3}$

The total resistance ( $R_T$ ) is the source voltage divided by the source current:

$R_T=\frac{V_S}{I_S}$

Now, replace $I_S$ by the previous expression and the total resistance would be:

$R_T=\frac{V_S}{V_S\cdot \frac{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}{R_1\cdot R_2\cdot R_3}}$

Simplify the expression and you must get:

$R_T=\frac{R_1\cdot R_2\cdot R_3}{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}$

The last step is to replace the values of the resistors:

$R_T=\frac{(6\Omega )\cdot (3\Omega)\cdot (12\Omega)}{(3\Omega)\cdot (12\Omega)+(6\Omega)\cdot (12\Omega)+(6\Omega)\cdot (3\Omega)}=\frac{12}{7}\Omega=1.7143\Omega$