<u>Given</u>:
The sides of the base of the triangle are 8, 15 and 17.
The height of the prism is 15 units.
We need to determine the volume of the right triangular prism.
<u>Area of the base of the triangle:</u>
The area of the base of the triangle can be determined using the Heron's formula.
Substituting a = 8, b = 15 and c = 17. Thus, we have;
Using Heron's formula, we have;
Thus, the area of the base of the right triangular prism is 36 square units.
<u>Volume of the right triangular prism:</u>
The volume of the right triangular prism can be determined using the formula,
where 
is the area of the base of the prism and h is the height of the prism.
Substituting the values, we have;
Thus, the volume of the right triangular prism is 450 cubic units.
Answer:0.006439
Step-by-step explanation:
Answer:
29%
Step-by-step explanation:
210-150/210 = 60/210 or 6/21
Now we have to find the percent out of 100 so we have to find out 100/21 to see what we have to multiply by to get to 100 so we can do the same with the 2 (numerator) so 1000/21= 4 16/21
then we have to multiply the 6 by 4 16/21 which is about 29%
Answer:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Step-by-step explanation:
We have a rectangular base, that its twice as long as it is wide.
It must hold 12 yd^3 of debris.
We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).
The surface is equal to:
The volume restriction is:
If we replace h in the surface equation, we have:
To optimize, we derive and equal to zero:
![dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65](https://tex.z-dn.net/?f=dS%2Fdw%3D36%28-1%29w%5E%7B-2%7D%20%2B%208w%3D0%5C%5C%5C%5C36w%5E%7B-2%7D%3D8w%5C%5C%5C%5Cw%5E3%3D36%2F8%3D4.5%5C%5C%5C%5Cw%3D%5Csqrt%5B3%5D%7B4.5%7D%20%3D1.65)
Then, the height h is:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
