Simplify (2 3/5-1 2/3)×5/8
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I assume the base of S is the disk centered at the origin, or x² + y² ≤ r². Solving for y gives two solutions corresponding to the upper and lower halves of the circular boundary,
and the vertical distance between them - i.e. the side length of each cross section - is
Then the volume of each square cross section 4 (r² - x²) ∆x, and the volume of S is
By symmetry, this is the same as
which gives a volume of