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3 years ago

Which System of Inequalities could be used to solve the problem below?

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

7 0

a+y≤1000 and 25a+12.50y>15000 is the system of inequalities that could be used to solve the problem.

Step-by-step explanation:

Given,

Price of one adult ticket = a = $25

Price of one youth ticket = y = $12.50

Maximum people that can be hold by theater = 1000

Therefore;

The maximum number of people can be 1000 or less than that.

$a+y\leq 1000$

As they want to revenue to be more than 15,000 therefore,

$25a+12.50y>15000$

a+y≤1000 and 25a+12.50y>15000 is the system of inequalities that could be used to solve the problem.

Keywords: linear inequality, addition

Learn more about addition at:

#LearnwithBrainly

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Analyze the diagram below and complete the instructions that follow. Find AEB.

aleksandrvk [35]

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emmainna [20.7K]

Answer:

As per the properties of parallel lines and interior alternate angles postulate, we can prove that:

$m\angle 5+m\angle 2+m\angle 6=180^\circ$

Step-by-step explanation:

Given:

Line y || z

i.e. y is parallel to z.

To Prove:

$m\angle 5+m\angle 2+m\angle 6=180^\circ$

Solution:

It is given that the lines y and z are parallel to each other.

$m\angle 5, m\angle 1$ are interior alternate angles because lines y and z are parallel and one line AC cuts them.

So, $m\angle 5= m\angle 1$ ..... (1)

Similarly,

$m\angle 6, m\angle 3$ are interior alternate angles because lines y and z are parallel and one line AB cuts them.

So, $m\angle 6= m\angle 3$ ...... (2)

Now, we know that the line y is a straight line and A is one point on it.

Sum of all the angles on one side of a line on a point is always equal to $180^\circ$ .

i.e.

$m\angle 1+m\angle 2+m\angle 3=180^\circ$

Using equations (1) and (2):

We can see that:

$m\angle 5+m\angle 2+m\angle 6=180^\circ$

Hence proved.

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worty [1.4K]

Hello there!

"Compare the fraction 3/5 to 1/2 and then compare 2/6 to 1/2. Use symbols in your answer"

To make this easier, we will make it so that both fractions in each pair has like bases.

To make 3/5 and 1/2 have a like base, we must make the denominators 10. To do this, we will do the following:

(3*2)/(5*2) = 6/10

(1*5)/(2*5) = 5/10

Now we can easily compare and not worry about the denominator

So, let's just look at the numerators.

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That means:

3/5 > 1/2

Now, we must do the same for 2/6 and 1/2

We will make them both 6. So, we can leave 2/6 alone

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Now we have 2/6 and 3/6

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Our answers are:

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I hope I was able to help you!

~ Fire

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