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3 years ago

What is aspartame? EXPLAIN

Chemistry

2 answers:

maksim [4K]3 years ago

5 0

Answer:

Aspartame is some type of very sweet substance that is used as an artificial sweetener, and chiefly in low-calorie products. It is a derivative of aspartic acid and phenylalanine.

Explanation:

ki77a [65]3 years ago

3 0

Answer:

it's an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages. it's a methyl ester of the aspartic acid/phenylalanine dipeptide with the trade names NutraSweet, Equal, and Canderel

Explanation:

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The diagram shows a swinging pendulum. Which best explains what happens to the motion of the pendulum?

Degger [83]

It is swing and will slowly stop.

7 0

3 years ago

I need help with chem. How do I know if this is balanced ?

ivanzaharov [21]

https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equations/v/balancing-chemical-equations-introduction

this will help trust me

have a good day

6 0

3 years ago

30. The density of an unknown gas at 27°C and 2 atm pressure is equal with density of N2 gas at

Zanzabum

Answer:

Molar mass of the unknown gas is 64.6 g/mol

Explanation:

Let's think this excersise with the Ideal Gases Law.

We start from the N₂. At STP conditions we know that 1 mol of anything occupies 22.4L.

We apply: P . V = n . R . T

5 atm . V = 1 mol . 0.082 . 325K

V = (1 mol . 0.082 . 325K) / 5 atm = 5.33 L

It is reasonable to say that, if we have more pressure, we may have less volume.

As this is the volume for 1 mol of N₂, our mass is 28 g. Then, the density of the nitrogen and the unknown gas is 28 g/5.33L = 5.25 g/L

Our unknown gas has, this density at 27°C and 2 atm.

If we star from this, again: 1 mol of any gas occupy 22.4L at STP, we can calculate the volume for 1 mol at those conditions:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

1 atm . 22,4L / 273K = 2 atm . V₂ / 300K

Remember that the value for T° is Absolute (T°C + 273)

[ (1 atm . 22.4L / 273K) . 300K] / 2 atm = V₂ → 12.3L

This is the volume for 1 mol of the unknown gas at 2 atm and 27°C

We use density to determine the mass: 12.3 L . 5.25 g/L = 64.6 g

That's the molar mass: 64.6 g/mol

6 0

3 years ago

How can you tell if an electric charge is present?

Svetllana [295]

If an element is written with a plus (+) or minus (-) symbol in the superscript then the element is either an anion or cation ( ion)

Ex : H₂ -----> stable or elemental form

Na⁺------> Cation

Cl⁻------> Anion

Technically an atom have positive charge when it loses its valence electrons and negative charge when it gains electrons.

7 0

4 years ago

The reaction for the synthesis of ammonia N2(g) + 3 H2(g) → 2 NH3(g) is exothermic. Increasing the temperature applied to the sy

igomit [66]

Answer:

The correct statements are (II) and (III).

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

$N_2(g)+3H_2(g)\leftrightharpoons 2NH_3(g)$

This is a type of exothermic reaction because heat is released in the reaction.

On increasing the temperature

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in temperature occurs. As, this is an exothermic reaction, forward reaction will increase the temperature. Hence, the equilibrium will shift in the left direction.

And by moving to left side amount of ammonia will decrease accompanied by the change in the value of an equilibrium constant.

5 0

4 years ago