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matrenka [14]
3 years ago
14

A teacher surveys a sample of students from Lake Middle School. He asks the students where they’d like to go for a field trip. H

e records these results:
80 choose the aquarium.
60 choose the science center.
30 choose the planetarium.
40 choose the farm.
The teacher wants to figure out the relative frequency of a student choosing the aquarium. He will then estimate how many students out of all 1000 at the school are likely to choose the aquarium.
4) Write and solve a proportion that the teacher can use to estimate how many students in the whole school would choose the aquarium. Show your work.
Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

210 student's

Step-by-step explanation:

80 students chose the aquarium.

60 students chose the science center.

30 students chose the planetarium.

40 students chose the farm.

The students can't vote for more than one place, so you just add all the numbers together.

80 + 60 + 30 + 40 = 210 students

aleksley [76]3 years ago
6 0
80 choose the aquarium
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A. P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

Step-by-step explanation:

Working with an ordinary Normal Distribution of probability and trying to find the probabilities asked in it could be difficult, because there´s no easy method to find probabilities in a generic Normal Distribution (with mean μ=4 and STD σ=0.1). The recommended approach to this question is to use a process called "Normalize", this process let us translate the problem of any Normal Distribution to a Standard Normal Distribution (μ=0 and σ=1) where there´s easier ways to find probabilities in there. The "Normalization" goes as follows:

Suppose you want to know P(x<a) of the Normal Distribution you are working with:

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Where μ is the mean and σ is the STD of your Normal Distribution. Notice P(z<b) now it´s a probability in a Standard Normal Distribution, now we can find it using the available method to do so. My favorite is a chart (It´s attached to this answer) that contains a lot of probabilities in a Standard Normal Distribution. Let´s solve this as an example

A. We want to find the probability of the cork being defective (P(x<3.85) + P(x>4.15)). Now we find those separated and, then, add them for our answer.

Let´s begin with P(x<3.85), we start by normalizing that probability:

P(x<3.85)= P( (x-μ)/σ < (3.85-4)/0.1 )= P(z<-1.5)

And now it´s time to use the chart, it works like this: If you want P(z<c) and the decimal expansion of c=a.bd... , then:

P(z<c)=(a.b , d)

Where (a.b , d) are the coordinates of the probability in the chart. Keep in mind that will only work with "<" (It won´t work directly with P(z>c)) and we will do some extra work in those cases.

P(z<-1.5) is in the coordinates (-1.5 , 0)

P(z<-1.5)= 0.0668

P(x<3.85)= 0.0668

Now we are looking for P(x>4.15), let´s Normalize it too:

P(x>4.15)=P( (x-μ)/σ < (4.15-4)/0.1 )=P(z>1.5)

But remember the chart only work with "<", so we need to use a property of probability:

P(z>1.5)= 1 - P(z<1.5)

Using the chart:

P(z<1.5)=0.9332                             (1.5 , 0)

P(z>1.5)= 1 - 0.9332

P(z>1.5)= 0.0668

P(x>4.15)= 0.0668

And our final answer will be:

P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

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