Answer:
The general equation following the pattern becomes is 7 + (n - 1)×2
Where, n = The figure number - 1
Step-by-step explanation:
The pattern in the question can be described as follows;
Figure 2 = (5 + 2) squares boxes = 7 squares boxes
Figure 3 = (5 + 2 + 2) squares boxes
Figure 4 = (5 + 2 + 2 + 2) squares boxes
Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;
7 + (n - 1)×2.
Answer:
19.9 miles
Step-by-step explanation:
In this problem we have:
is the distance travelled during the 1st day
is the distance travelled during the 2nd day
is the distance travelled during the 3rd day
is the distance travelled during the 4th day
We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:
Which can be rewritten using the general formula:
This means that
By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:
So, the distance travelled on the 7th day is 19.9 miles.
31/40 is it in a fraction
<span>-5(3t-5)+7t=8t-6
-15t + 25 + 7t = 8t - 6
-15t + 7t - 8t = -6 - 25
-16t = -31
16t = 31
t = 31/16 = 1.9375</span>
Answer: The graph is attached.
Step-by-step explanation: The given functions whose graphs are to be compared are as follows:
In the attached figure, the graphs of both (A) and (B) are shown. We can easily see see from there, the shapes of both the graphs are same.
But, at x = 0, y = ∞ and at x = ∞, y = 0 in graph (A).
At x = 0, y = ∞ and at x = ∞, y = 6 in graph (B).
Thus, the comparison can be seen in the figure very clearly.