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Delvig [45]
3 years ago
11

Describe the end behavior of the following function f(x)=-2x^4-x^3+3

Mathematics
1 answer:
djyliett [7]3 years ago
8 0
See attachments for the answers.

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Please help me worth 10 points
JulsSmile [24]

Answer:

50/50

Step-by-step explanation:

6 0
3 years ago
The sum of three consecutive numbers is 72. What are the smallest of these three numbers?
strojnjashka [21]
X=small number x+1= second x+2= third 3x+3=72 3x=69 x=23 smallest number
6 0
3 years ago
Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
Uses
g100num [7]

Answer:

27 smoothies

Step-by-step explanation:

if you have 27 cups and one requires one cup, it would be 27 smoothies Katherine can make :)

5 0
3 years ago
Rewrite the equation by completing the square g(x) = x^2 - x - 6
borishaifa [10]

Answer:

g(x)=x2−x−6g(x)=x2-x-6

Set x2−x−6x2-x-6 equal to 00.

x2−x−6=0x2-x-6=0

Solve for xx.

Tap for fewer steps...

Factor x2−x−6x2-x-6 using the AC method.

Tap for more steps...

(x−3)(x+2)=0(x-3)(x+2)=0

If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.

x−3=0x-3=0

x+2=0x+2=0

Set x−3x-3 equal to 00 and solve for xx.

Tap for more steps...

x=3x=3

Set x+2x+2 equal to 00 and solve for xx.

Tap for more steps...

x=−2x=-2

The final solution is all the values that make (x−3)(x+2)=0(x-3)(x+2)=0 true.

x=3,−2

5 0
3 years ago
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