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2 years ago

The equation 6x - 5y = 14 is written in standard form. Which point lies on

Mathematics

1 answer:

dimaraw [331]2 years ago

4 0

Answer= H (-1, -4)

Explanation= 6(-1) - 5(-4) = 14
(-6) + (20) = 14
14=14 * it works !
GOODLUCK!

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Plsss answer I will mark as brilliant

Papessa [141]

Answer:

10p because when a number is with a letter its always multipucation

like 11x = 11x1

4 0

2 years ago

PLEASE HELP! find (1,2) obtained by translating 2 units down followed by a rotation of 180 counterclockwise.

N76 [4]

Answer:

Please check the explanation.

Step-by-step explanation:

Translating two units down means we need to subtract two units from the y-coordinate. i.e

(x, y) → (x, y-2)

We are given that the original point is (1, 2), and we have to find the image of (2, 4) obtained by translating 2 units down followed by a rotation of 180 counterclockwise.

FOR (1, 2)

Given

P(1, 2)

First translation: Translating two units down

(x, y) → (x, y-2)

P(1, 2) → P'(1, 2-2) → P'(1, 0)

Second transformation: Rotation of 180 counterclockwise.

Rotation of 180 counterclockwise will make both 'x' and 'y' coordinates negative. i.e

(x, y) → (-x, -y)

Thus, after second transformation

P'(1, 0) → (-1, 0)

Thus, the image of (1, 2) obtained by translating 2 units down followed by a rotation of 180 counterclockwise will be: (-1, 0)

FOR (2, 4)

Given

P(2, 4)

First translation: Translating two units down

(x, y) → (x, y-2)

P(2, 4) → P'(2, 4-2) → P'(2, 2)

Second transformation: Rotation of 180 counterclockwise.

Rotation of 180 counterclockwise will make both 'x' and 'y' coordinates negative. i.e

(x, y) → (-x, -y)

Thus, after the second transformation

P'(2, 2) → (-2, -2)

Thus, the image of (2, 4) obtained by translating 2 units down followed by a rotation of 180 counterclockwise will be: (-2, -2)

6 0

3 years ago

Pleasee help asap i dont have much time worth 10 points

uysha [10]

The answer is E
step by step explanation:

6 0

3 years ago

Read 2 more answers

The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15

katrin [286]

<h2>Hello!</h2>

The answer is: The first graphic representation.

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

$h(t)=-16.1t^2 + 150\\0=-16.1t^2 + 150\\16.1t^2=150\\t^2=\frac{150}{16.1}=9.32\\t=+-\sqrt{9.32}=+-3.05\\t1=3.05\\t2=-305$

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

$a=-1\\b=0\\c=150$

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

8 0

3 years ago

Read 2 more answers

What is the range of f?

zhannawk [14.2K]

Answer: $[-3,7]$

Step-by-step explanation:

The range of a function is the set of y-values

4 0

2 years ago