Answer:
![Accept = 69.44\%](https://tex.z-dn.net/?f=Accept%20%3D%2069.44%5C%25)
![Reject = 11](https://tex.z-dn.net/?f=Reject%20%3D%2011)
Step-by-step explanation:
Given
See attachment for dataset
Solving (a): Percentage to accept
The percentage to accept are flea collars that range between 14mg to 16mg (inclusive)
From the attachment, we have:
![Total = 36](https://tex.z-dn.net/?f=Total%20%3D%2036)
--- Number of 14mg to 16mg
So, the percentage to accept is:
![Accept = \frac{n(14mg-16mg)}{Total} * 100\%](https://tex.z-dn.net/?f=Accept%20%3D%20%5Cfrac%7Bn%2814mg-16mg%29%7D%7BTotal%7D%20%2A%20100%5C%25)
![Accept = \frac{25}{36} * 100\%](https://tex.z-dn.net/?f=Accept%20%3D%20%5Cfrac%7B25%7D%7B36%7D%20%2A%20100%5C%25)
![Accept = 0.6944 * 100\%](https://tex.z-dn.net/?f=Accept%20%3D%200.6944%20%2A%20100%5C%25)
![Accept = 69.44\%](https://tex.z-dn.net/?f=Accept%20%3D%2069.44%5C%25)
Solving (b): Collars to reject
In (a), we have:
![n(14mg-16mg) =25](https://tex.z-dn.net/?f=n%2814mg-16mg%29%20%3D25)
The number to reject is then calculated by subtracting the collars to accept from the total (this is called complement rule)
So, we have:
![Reject = Total - n(14mg - 16mg)](https://tex.z-dn.net/?f=Reject%20%3D%20Total%20-%20n%2814mg%20-%2016mg%29)
![Reject = 36 - 25](https://tex.z-dn.net/?f=Reject%20%3D%2036%20-%2025)
![Reject = 11](https://tex.z-dn.net/?f=Reject%20%3D%2011)
<em>11 will be rejected</em>
<em>Hope</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
3 + 2 = 5
<span>80p / 5 = 16p </span>
<span>1st part = 2(16p) = 32p </span>
<span>2nd part = 3(16p) = 48p </span>
<span>48p : 32p :: 3 : 2 </span>
Wages wages wages wages wages wages wages wages wages vwages wages wages wages wages wages wages wages wages wages wages wages wages
Answer:
Can you please include the complete question?
Step-by-step explanation: