The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
d. 
Step-by-step explanation:
This is a 45-45-90 right triangle with a Pythagorean triple of (x, x, x√2). Because this is a 45-45-90, both legs have the same measure, namely 8. Therefore, according to the Pythagorean triple, x = 8 (NOT the x in your diagram...the x in the Pythagorean triple). That means that the hypotenuse has a measure of , which is d.
Answer:
The person traveled 540 miles by plane and 60 miles by automobile.
Step-by-step explanation:
The options are not given to choose from, but this question can be solved as it will only have one answer.
Let the miles traveled by automobile be = x
Then, miles traveled by airplane will be = 9x
Now, the total trip length was = 600 miles
I would try going with h =7/2 if that is wrong just rate me 1
Answer:
200,000
Step-by-step explanation:
