Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Step-by-step explanation:
4(px + 1) = 64
Step 1: Add -4 to both sides.
4px + 4 -4 = 64 + -4
4px = 60
Step 2: Divide both sides by 4p.
<u>4px</u> = <u>60</u>
4p 4p
x = <u>15</u>
p
The solutions to f(x) = 64 is x = 7 and x = –7.
Solution:
Given data:
– – – – (1)
– – – – (2)
To find the solutions to f(x) = 64.
Equate equation (1) and (2), we get
Subtract 15 from both sides of the equation.
Taking square root on both sides of the equation, we get
x = ±7
The solutions to f(x) = 64 is x = 7 and x = –7.
Answer:
They have both root common .